Beam Radius Calculations
The half-power point occurs when the power drops to half of its maximum value. Mathematically, this is when
Taking square root
Solving numerically for \(J_{1}(x) = \frac{x}{2\sqrt{2}}\), we get
Substituting \(k = 2\pi/\lambda\) and \(a = \frac{D}{2}\)
Using the fact that for small angles \(\sin(\theta) \approx \theta\), and on converting to degrees, we get
For aperture, \(a\) and wavelength \(\lambda\), since \(2a = d\) and substituting \(\lambda = \frac{c}{f}\) we get
Parameters |
Values |
||
|---|---|---|---|
Configuration |
LEO 1200 |
MEO 10000 |
GEO35786 |
Altitude (km) |
1200 |
10000 |
35786 |
Band |
S band |
S band |
S band |
Antenna Aperture Radius (m) |
1 |
5 |
11 |
Channel Frequency (GHz) |
2 |
2 |
2 |
\(\theta_{3dB}\) (or \(\theta_{HPBW})\) (Calculation provided below) |
5.25 |
1.05 |
0.476 |
Beam Radius (km) |
110.26 |
183.28 |
297.31 |
Table-1: Antenna and Beam Parameters for LEO, MEO, and GEO Satellite Configurations
Parameters |
Values |
||
|---|---|---|---|
Configuration |
LEO 1200 |
MEO 10000 |
GEO35786 |
Altitude (km) |
1200 |
10000 |
35786 |
Band |
K band |
K band |
K band |
Antenna Aperture Radius (m) |
0.25 |
1 |
2.5 |
Channel Frequency (GHz) |
20 |
20 |
20 |
\(\theta_{3dB}\) (or \(\theta_{HPBW})\) (Calculation provided below) |
2.1 |
0.525 |
0.21 |
Beam Radius (km) |
44 |
91.63 |
131.16 |
Table-2: Antenna and Beam Parameters for LEO, MEO, and GEO Satellite Configurations
Hexagonal tessellation based on beam radius
In a hexagonal tessellation:
Each beam is represented by a hexagon.
The beams are arranged in a honeycomb pattern to maximize coverage and minimize overlap.
The beam radius, \(R\) is the distance from the centre of the beam to its edge, where the power drops to a specified level (e.g., half-power or ‑3 dB).
In a hexagonal grid, the distance between beam centers (beam spacing) is \(\sqrt{3} \cdot R\)